All equations of the form a x 2 b x c = 0 can be solved using the quadratic formula 2 a − b ± b 2 − 4 a c The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction x^ {2}yxy^ {2}=4 x 2 y x y 2 = 4 Subtract 4 from both sides of the equationHola mi gente, en este video comprobaremos que la ecuación diferencial (xyy^2x^2)dxx^2dy=0 es homogénea y a su vez hallaremos su solución generalPor favoStart with $(x y)^2$, multiply out to get $x^2 y^2 xy yx$ and then collect like terms to get the normal form $x^2 2xy y^2$ "Multiplying out and collecting like terms" is a decision procedure for this kind of problem
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X^2+xy+y^2 formula- · x^2xyy^2 = 1 (xy)(xy)=1 (Factored) (xy)^2=1 (Rewritten) xy=1 or xy=1 because a square root can be a positive or a negative (Square root both sides) y= x1 y= x1 (simply rearrange the variables using algebra) y = {(x1),(x1)} < ANSWERFor any fixed $y$, the solutions of $x^2xyy^2=0$ are $$x=\frac{y \pm\sqrt{3y^2}}{2}$$ If $y\ne 0$, the number under the square root sign is negative, and therefore $\sqrt{3y^2}$ is not a real number, so $x$ is not a real number
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Hint go the other way!This formula is also referred to as the binomial formula or the binomial identity Using summation notation , it can be written as ( x y ) n = ∑ k = 0 n ( n k ) x n − k y k = ∑ k = 0 n ( n k ) x k y n − k {\displaystyle (xy)^{n}=\sum _{k=0}^{n}{n \choose k}x^{n · It can be factored as x^2 y^2 = (xy)(xy) Notice that when you multiply (xy) by (xy) then the terms in xy cancel out, leaving x^2y^2 (xy)(xy) = x^2xyyxy^2 = x^2xyxyy^2 = x^2y^2 In general, if you spot something in the form a^2b^2 then it can be factored as (ab)(ab) For example 9x^216y^2 = (3x)^2(4y)^2 = (3x4y)(3x4y)
Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with stepbystep explanations, just like a math tutor · x^2 xy y^2 = 1 Find the largest value of y which satisfies the above equation and the corresponding value of x (x is real) · #(x^2y^22xy)(xy)=x^3x^2yxy^2y^32x^2y2xy^2# #rArr x^3y^33x^2y3xy^2# Always expand each term in the bracket by all the other terms in the other brackets, but never multiply two or more terms in the same bracket
Derivative x^2(xy)^2 = x^2y^2 Extended Keyboard;Show, by left side, that $$\frac{x^3y^3}{xy} = x^2xyy^2,$$ or $$\frac{x^3y^3}{x^2xyy^2} = xy$$ You may read about "Long Division of Polynomials" See also LINK for knowing the processFactor x^2xyxy Factor out the greatest common factor from each group Tap for more steps Group the first two terms and the last two terms Factor out the greatest common factor (GCF) from each group Factor the polynomial by factoring out the greatest common factor, Rewrite as
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Please Subscribe here, thank you!!!X^2y^2z^2xyyzzx=0 multiplying the RHS and LHS by 2 we get , 2 x^2y^2z^2xyyzzx =0 or, (xy)^2(yz)^2(zx)^2=0 since in LHS there are only squared terms,ie they cannot beX y = 2 Squaring both sides (x y) ^ 2 = 2 ^ 2 x^2 y^2 2xy = 4 As x^2 y^2 = 2 (given), 2 2xy = 4 2xy = 2 xy = 1 That's your answer Hope it helps!
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Adding fractions that have a common denominator 22 Adding up the two equivalent fractions Add the two equivalent fractions which now have a common denominator Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible x2 • x (y2) x3 y2This is always true with real numbers, but not always for imaginary numbers We have ( x y) 2 = ( x y) ( x y) = x y x y = x x y y = x 2 × y 2 (xy)^2= (xy) (xy)=x {\color {#D61F06} {yx}} y=x {\color {#D61F06} {xy}}y=x^2 \times y^2\ _\square (xy)2 = (xy)(xy) = xyxy = xxyy = x2 ×y2 For noncommutative operators under some algebraic · Favorite Answer x^2xy y^2 this equation can't be factor because there is no two numbers whose product and sum is one RealArsenalFan Lv 4 1 decade ago You can use a method called "completing a square" Your signs look a bit strange However, after completing a square you will have an answer that looks like this,
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Xy=12, (x^2y^2)=25 then what is the value of (xy)2^2;Find the solution of the differential equation that satisfies the given initial conditionxy' y = y^2, y(1) = 1X^2 y^2 = x^2 2xy y^2 2xy = (x y)^2 2xy x^2 y^2 = x^2 2xy y^2 2xy = (x y)^2 2xy ∴ (i) x^2 y^2 = (x y)^2 2xy (ii) x^2 y^2 = (x y)^2 2xy
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Click here👆to get an answer to your question ️ Solve the differential equation, (x^2 xy)dy = (x^2 y^2) dxX^{2}\left(2y\right)xy^{2}1=0 All equations of the form ax^{2}bxc=0 can be solved using the quadratic formula \frac{b±\sqrt{b^{2}4ac}}{2a} The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction · Using the simple formula ( x y )^2 = x^2 y^2 2*x*y I have proved that 2 = 4 Here is the proof 8 = 8 412 = 1624 (since 412= 8 & 16 –24 = 8) Now add 9 to both sides 4 – 12 9 = 16 – 24 9 2*2 2*2*3 3*3 = 4*4 – 2*4*3 3*3 2^2 2*2*3 3^2 = 4^2 – 2*4*3 3^2 this steplooks like the formula x2 y2 2*x*y = ( x y )2 ( 2 – 3 )^2 = ( 4 – 3 )^2 So 2 – 3= 4
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Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, historySome Useful Algebra Formulas Just remembering Algebra (math) formulas are not going to help you to crack any examinations, one should have the ability to execute these formulas in the exam hall To do that, one has to practice the various types of algebraic math problems repeatedly Some Important Formulas of Algebra Square Formula 01You can put this solution on YOUR website!
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· In probability theory and statistics, variance is the expectation of the squared deviation of a random variable from its meanIn other words, it measures how far a set of numbers is spread out from their average value Variance has a central role in statistics, where some ideas that use it include descriptive statistics, statistical inference, hypothesis testing, goodness of fit, andExpand (x−y)(x2 xyy2) ( x y) ( x 2 x y y 2) by multiplying each term in the first expression by each term in the second expression Simplify terms Tap for more steps Simplify each term Tap for more steps Multiply x x by x 2 x 2 by adding the exponents Tap for more steps Multiply x x by x 2 x 2However, the figure resulting from removing six singular points is one Its name arises because it was discovered by Jakob Steiner when he was in Rome in 1844
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Algebra Divide (x^2y^2)/ (xy) x2 − y2 x − y x 2 y 2 x y Since both terms are perfect squares, factor using the difference of squares formula, a2 −b2 = (ab)(a−b) a 2 b 2 = ( a b) ( a b) where a = x a = x and b = y b = y (xy)(x −y) x−y ( x y) ( x y) x y Cancel the common factor of x−y x yCylindrical decomposition((x^2 x y y^2) 1> 0, {x, y}) tangent plane to (x^2 x y y^2) 1 at (x,y)=(1,2) SymmetricReduction((x^2 x y y^2) 1, {x^21, x}) (x^2 x y y^2) 1 > 0;The Roman surface or Steiner surface is a selfintersecting mapping of the real projective plane into threedimensional space, with an unusually high degree of symmetryThis mapping is not an immersion of the projective plane;
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X 2 d x − y 2 d x x d y 2 = 0 d x x d y 2 − y 2 d x x 2 = 0 d x d ( y 2 x) = 0 x y 2 x = C It seems to me that there is a sign mistake somewhere Share edited Nov 11 ' at 2301 answered Nov 11 ' at 2256 AryadevaCircle on a Graph Let us put a circle of radius 5 on a graph Now let's work out exactly where all the points are We make a rightangled triangle And then use Pythagoras x 2 y 2 = 5 2 There are an infinite number of those points, here are some examples · In mathematics, trigonometric substitution is the substitution of trigonometric functions for other expressions In calculus, trigonometric substitution is a technique for evaluating integralsMoreover, one may use the trigonometric identities to simplify certain integrals containing radical expressions Like other methods of integration by substitution, when evaluating a definite
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The example below demonstrates how the Quadratic Formula is sometimes used to help in solving, and shows how involved your computations might get Solve the system x 2 – xy y 2 = 21 x 2 2xy – 8y 2 = 0 This system represents an ellipse and a set of straight linesCompute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, historyI'll use the following formulas #color(blue)(x^2 y^2 = (xy)(xy))# #color(purple)(x^3 y^3 = (xy)(x^2 xy y^2))# #color(green)((xy)^2 = x^2 2xy y^2)#
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2310 · If x^2 xy y^3 = 1, find the value of y" at the point where x = 1 Video Transcript in this problem were given any question west by about enough for derivative on exit onAlgebra Factor x^2y^2 x2 − y2 x 2 y 2 Since both terms are perfect squares, factor using the difference of squares formula, a2 −b2 = (ab)(a−b) a 2 b 2 = ( a b) ( aCompute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science
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Since y^2 = x − 2 is a relation (has more than 1 yvalue for each xvalue) and not a function (which has a maximum of 1 yvalue for each xvalue), we need to split it into 2 separate functions and graph them together So the first one will be y 1 = √ (x − 2) and the second one is y 2 = −√ (x − 2)The Gaussian integral, also known as the Euler–Poisson integral, is the integral of the Gaussian function = over the entire real line Named after the German mathematician Carl Friedrich Gauss, the integral is = Abraham de Moivre originally discovered this type of integral in 1733, while Gauss published the precise integral in 1809 The integral has a wide range of applications · I'm not very good at implicit differentiation could someone please help me out I need to differentiate x^2xyy^2=3 using implicit differentiation if someone could explain the steps I would be very greatful
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Manipulate c in (x^2 x y y^2) 1 = cThis equation is in standard form a x 2 b x c = 0 Substitute 1 for a, − 2 x for b, and x 2 for c in the quadratic formula, 2 a − b ± b 2 − 4 a c y=\frac {\left (2x\right)±\sqrt {\left (2x\right)^ {2}4x^ {2}}} {2} y = 2 − ( − 2 x) ± ( − 2 x) 2 − 4 x 2 Square 2x Square − 2 x12 x 2 2xy y 2 is a perfect square It factors into (xy)•(xy) which is another way of writing (xy) 2 How to recognize a perfect square trinomial • It has three terms • Two of its terms are perfect squares themselves • The remaining term is twice the product of the square roots of the other two terms Final result (x y) 2
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